Invision Community 5: A video walkthrough creating a custom theme and homepage By Matt Thursday at 04:02 PM
TSP Posted May 27 Posted May 27 Steps to reproduce: Create a test topic in a forum where guests does NOT have permission to post new topics Reply with a test account, or temporarily allow guests to post topics and replies. If you replied with a test account: delete the test account so the reply becomes a guest post If you posted as a guest: remember to reset the forum permissions to once again disallow guest topics/replies As a moderator: select the reply and split it into a new topic in the same forum with your moderator tools You should be redirected to the new topic created by splitting the posts Instead you'll get an error page: "You do not have permission to view this topic." (Error code: 2F173/K) The reason is that the new topic is saved to the database with the approved column set to -3. Which in system/Content/Content.php is documented as: "@li -3 is a post made by a guest using the "post before register" feature" Please note that this will happen even if the system "Post before register" is disabled. It shouldn't happen in either cases. Also; since there is no way to get a list of topics and replies hidden for this reason, it's not possible to save the topic from the interface, you'll have to manually fix it in the database. I think this happens because of the following code for the function createItem in system/Content/Item.php. I'm pretty sure you'll have to fix the logic for both the approved and hidden switch. <?php case 'approved': if ( $hidden === NULL ) { if ( !$author->member_id and $container and !$container->can( 'add', $author, FALSE ) ) { $val = -3; } else { $val = static::moderateNewItems( $author, $container ) ? 0 : 1; } } else { $val = \intval( !$hidden ); } break; case 'hidden': if ( $hidden === NULL ) { if ( !$author->member_id and $container and !$container->can( 'add', $author, FALSE ) ) { $val = -3; } else { $val = static::moderateNewItems( $author, $container ) ? 1 : 0; } } else { $val = \intval( $hidden ); } break; SeNioR- 1
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