Hi folks,

I was going through the following page:

And cannot get the following to work:

// Get the select object
$select = \IPS\Db::i()->select( '*', 'my_table', array( 'status=?',  ));
// Now, get the number of results returned
$results = count( $select );

The $results = count ( $select) line is the problem, if I comment it out the error goes away.  Am I missing something obvious here?

Cheers 🙂

I should add that there are records in the table that match the query string, so results should be coming back.

status = what?

oops sorry, that's a typo there.

$select = \IPS\Db::i()->select( '*', 'my_table', array( 'status=?', 0));

$select = \IPS\Db::i()->select( '* as cnt, 'my_table', array( 'status=?', 0))->first();

The result is in $select[‘cnt’]

That seems okay. But how are you using the $select variable after that? Maybe that's the problem. Try posting some of the code above/below that line.

47 minutes ago, Adriano Faria said:

$select = \IPS\Db::i()->select( '* as cnt, 'my_table', array( 'status=?', 0))->first();

The result is in $select[‘cnt’]

Thanks - I tried this but am now getting this error:

$select = \IPS\Db::i()->select('COUNT(*) as cnt', 'hangman_phrase', array('status=?', 0), array('member_id!=', $member->member_id));
$result = $select['cnt'];

Cannot use object of type IPS\Db\Select as array

 

48 minutes ago, teraßyte said:

That seems okay. But how are you using the $select variable after that? Maybe that's the problem. Try posting some of the code above/below that line.

I removed all the code after the count($select) line and the error still occurs. I get the feeling it's probably something so stupidly obviously I'll kick myself when I see it!

2 minutes ago, Mick79 said:

Thanks - I tried this but am now getting this error:

I don’t see the ->first() there.

$count = \IPS\Db::i()->select( 'count(*)', 'hangman_phrase', array('status=0 AND member_id!=?', $member->member_id ) )->first();
print $count;

You have 2 arrays there and forgot the ->first ().